Jika a, b, c memenuhisistem persamaan
a + 2b - c = 9
2a - b + 3c = -2
-a + b + 2c = -1
Nilai a, b, c berturut – turut adalah ...
a + 2b - c = 9
2a - b + 3c = -2
-a + b + 2c = -1
Nilai a, b, c berturut – turut adalah ...
Jawaban:
a + 2b - c = 9 |x2| 2a + 4b - 2c = 18
2a - b + 3c = -2 |x1| 2a - b + 3c = -2
_____________-
5b - 5c = 20
a + 2b - c = 9
-a + b + 2c = -1
____________+
3b + c = 8
5b - 5c = 20 |x3| 15b - 15c = 60
3b + c = 8 |x5| 15b + 5c = 40
____________-
-20c = 20
c = -1
3b + c = 8
3b + (-1) = 8
3b = 9
b = 3
a + 2b - c = 9
a + 2(3) - (-1) = 9
a + 6 + 1 = 9
a + 7 = 9
a = 2
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